X^2+24x=140

Solution for X^2+24x=140 equation:

X^2+24X=140

We move all terms to the left:

X^2+24X-(140)=0

a = 1; b = 24; c = -140;
Δ = b2-4ac
Δ = 242-4·1·(-140)
Δ = 1136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1136}=\sqrt{16*71}=\sqrt{16}*\sqrt{71}=4\sqrt{71}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{71}}{2*1}=\frac{-24-4\sqrt{71}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{71}}{2*1}=\frac{-24+4\sqrt{71}}{2}
$